Two resistances of $$400$$ Ω and $$800$$ Ω are connected in series with a $$6$$ volt battery of negligible internal resistance. A voltmeter of resistance $$10$$, $$000$$ Ω is used to measure the potential difference across $$400$$ Ω. The error in the measurement of potential difference in volts, approximately, is

Question

Two resistances of $$400$$ Ω and $$800$$ Ω are connected in series with a $$6$$ volt battery of negligible internal resistance. A voltmeter of resistance $$10$$, $$000$$  Ω is used to measure the potential difference across $$400$$ Ω. The error in the measurement of potential difference in volts, approximately, is

Infinity Learn · Accepted Answer

Before connecting voltmeter, potential difference across $$400$$  Ω resistance isVi $$=$$  $$400400$$ $$+800$$ × $$6=2VAfter$$ connecting voltmeter, equivalent resistancebetween A and B $$400$$ × $$10000400$$ $$+10000=$$ $$384.6$$ ΩHence, potential difference measured by voltmeterVf $$=$$  $$384.6384.6$$ $$+800$$× $$6=1.95$$ VError in measurement $$=Vi$$ − Vf $$=$$ $$2$$−$$1.95=0.05$$  V

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Two resistances of 400 Ω and 800 Ω are connected in series with a 6 volt battery of negligible internal resistance. A voltmeter of resistance 10, 000 Ω is used to measure the potential difference across 400 Ω. The error in the measurement of potential difference in volts, approximately, is

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