Two resistances are connected in two gaps of a meter bridge. The balance point is 20cm from the zero end. A resistance of 15 Ωis connected in series with the smaller of the two. The null point shifts to 40cm. Then value of the smaller resistance is:
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a
3 Ω
b
6 Ω
c
9 Ω
d
12 Ω
answer is C.
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Detailed Solution
GivenBalancing length l=20 cmResistance= 15 ΩIf the unknown resistances are P and Q, then for first case we have at null point 20cm PQ=20100−20or Q=4P ⇒P