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Q.

Two resistances are connected in two gaps of a metre bridge. The balance point is 20 cm from the zero end. A resistance of 15 ohm is connected in series with the smaller of the two. The null point shifts to 40 cm. The value of the smaller resistance in ohm is

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a

3

b

6

c

9

d

12

answer is C.

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Detailed Solution

Let S and fi be two resistances connected in the twogaps of metre bridge and S > R. We haveS=100−llR=100−2020R=4R……….(1)When 15 Ω is added to resistance R, thenS=100−4040(R+15)=64(R+15)………(2)From eqs. (1) and [2), we get4R=64(R+15)Solving , we get R =9 Ω

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Two resistances are connected in two gaps of a metre bridge. The balance point is 20 cm from the zero end. A resistance of 15 ohm is connected in series with the smaller of the two. The null point shifts to 40 cm. The value of the smaller resistance in ohm is