Two resistances are joined in parallel whose resultant is 68ohm. One of the resistance wires is broken and the effective resistance becomes 2 Ω Then the resistance in ohm of the wire that got broken was
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
3/5
b
2
c
6/5
d
3
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
If resistances are R1 and R2 then R1R2R1+R2 = 68 …..(i)Suppose R2 is broken then R1 = 2 Ω …..(ii)On solving equations (i) and (ii), we get R2 = 6/5 Ω