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Q.

Two resistances are joined in parallel whose resultant is 68ohm. One of the resistance wires is broken and the effective resistance becomes 2 Ω Then the resistance in ohm of the wire that got broken was

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a

3/5

b

2

c

6/5

d

3

answer is C.

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Detailed Solution

If resistances are R1 and R2 then R1R2R1+R2 = 68         …..(i)Suppose R2 is broken then R1 = 2 Ω                            …..(ii)On solving equations (i) and (ii), we get R2 = 6/5 Ω
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