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Two resistor R1=(24±0.5)Ω and R(8±0.3)Ω are joined in series. The equivalent resistance is

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a
32±0.33Ω
b
32±0.8Ω
c
32±0.2Ω
d
32±0.5Ω

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detailed solution

Correct option is B

R1=(24±0.5)ΩR2=(8±0.3)ΩR3=R1+R2=(32±0.8)Ω


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