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Questions  

Two resistors are connected (i) in series (ii) in parallel. The equivalent resistance in the two cases are 9 ohm and 2 ohm respectively. Then the resistances of the component resistors are

a
2 ohm and 7 ohm
b
3 ohm and 6 ohm
c
3 ohm and 9 ohm
d
5 ohm and 4 ohm

detailed solution

Correct option is B

R1+R2 =9  and  R1R2R1+R2 = 2  ⇒ R1R2=18 R1−R2 = R1+R2 2 − 4R1R2 = 81−72=3R1=6  Ω,  R2=3  Ω

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