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Q.

Two resistors are connected in a series across 5V rms source of alternating potential. The potential difference across 6Ω resistor is3V . If R is replaced by a pure inductor L of such magnitude that current remains same, then the potential difference across L is

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a

1V

b

2V

c

3V

d

4V

answer is D.

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Detailed Solution

⇒Vms across 6Ω=3V ⇒3=6IV   ∴IV=0.5A IV=12=562+XL 2,XL=8ΩNow, VL=IV. XL=12×8=4V
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