Two resistors are connected in series across 5 volt r.m.s. source of alternating potential as shown in figure. The potential difference across 6 Ω resistor is 3V. If R is replaced by pure inductor L of such magnitude that current remains same, potential difference across L is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1 V
b
2 V
c
3 V
d
4 V
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Vrms(6Ω)=3 V=6 IV ∴ IV=0.5 AIV=12=562+XL2⇒XL=8 ΩNow, VL=IV ⋅ XL=12 × 8 = 4 V
Two resistors are connected in series across 5 volt r.m.s. source of alternating potential as shown in figure. The potential difference across 6 Ω resistor is 3V. If R is replaced by pure inductor L of such magnitude that current remains same, potential difference across L is