Questions
Two resistors of resistances are connected in parallel, then the equivalent resistance in parallel is (in ohm)
detailed solution
Correct option is A
The equivalent resistance of parallel combination is R'=R1R2R1+R2=2003=66.7ΩFrom 1R'=1R1+1R2, we get ΔR'R'2=ΔR1R12+ΔR2R22ΔR'=R'2ΔR1R12+R'2ΔR2R22=66.710023+66.720024=1.8ΩHence, R'=(66.7±1.8)ΩTalk to our academic expert!
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