Q.

Two rigid bodies A and B rotate with angular momenta LA and LB, respectively. The moments of inertia of A and B about the axes of rotation are IA and IB, respectively. If IA=IB/4 and LA=5LB, Then the ratio of rotational kinetic energy KA of A to the rotational kinetic energy KB of B is given by

Moderate

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By Expert Faculty of Sri Chaitanya

a

KAKB=254

b

KAKB=54

c

KAKB=14

d

KAKB=100

answer is 4.

(Detailed Solution Below)

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Detailed Solution

KA=LA22lA=25LB22lBKB=LB22lBNow, KAKB=25×4=100
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