Q.
Two rigid bodies A and B rotate with angular momenta LA and LB respectively. The moments of inertia of A and B about the axes of rotation are IA and IB respectively. If IA = IB/4 and LA = 5LB, Then the ratio of rotational kinetic energy KA of A to the rotational kinetic energy KB of B is given by
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a
KAKB=254
b
KAKB=54
c
KAKB=14
d
KAKB=100
answer is D.
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Detailed Solution
KA=LA22lA=4×25LB22lB KB=LB22lB Now, KAKB=25×4=100
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