Questions

# Two rigid bodies A and B rotate with angular momenta LA and LB respectively. The moments of inertia of A and B about the axes of rotation are IA and IB respectively. If IA = IB/4 and LA = 5LB, Then the ratio of rotational kinetic energy KA of A to the rotational kinetic energy KB of B is given by

## Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
KAKB=254
b
KAKB=54
c
KAKB=14
d
KAKB=100

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is D

KA=LA22lA=4×25LB22lB      KB=LB22lB Now, KAKB=25×4=100

+91

Are you a Sri Chaitanya student?

Similar Questions

The condition of equilibrium is satisfied when resultant of all forces acting on body vanishes and also no net torque acts on the body. However body can be different types of equilibrium as stable, unstable, neutral or may be having pure rotation when no resultant force acts on the body. Different conditions of equilibrium or rotational motion can be known by different types of energy it possesses. Column I mentions the state of body and column II mentions the type of energy it possesses. Match the correct options in two columns

COLUMN_I                                                             COLUMN_II

A)  Body in stable equilibrium                P) Rotational kinetic energy

B)  Body in unstable equilibrium           Q) Minimum potential

energy

C)   Body in neutral equilibrium         R)Maximum potential energy

D) Body in pure rotational motion     S) Constant potential energy