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Two rigid bodies A and B rotate with angular momenta L_A and L_B, respectively. The moments of inertia of A and B about the axes of rotation are I_A and I_B respectively. If $I_{A} = I_{B} / 4 and L_{A} = 5 L_{B}$ ,then the ratio of rotational kinetic energy K_A of A to the rotational kinetic energy K_B of B is given by

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KAKB=254

KAKB=54

KAKB=14

KAKB=100

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detailed solution

Correct option is D

KA=LA22lA=25LB22lB4KB=LB22lB Now, KAKB=25×4=100

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Two rigid bodies A and B rotate with angular momenta LA and LB, respectively. The moments of inertia of A and B about the axes of rotation are IA and IB respectively. If IA=IB/4 and LA=5LB,then the ratio of rotational kinetic energy KA of A to the rotational kinetic energy KB of B is given by

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