Two rings of the same radius r and mass m are placed such that they are attached to their rims and their planes are perpendicular to each other as shown in the figure. The moment of inertia of the system about a diameter of one of the rings and passing through the point of contact is
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a
3mr22
b
3mr2
c
5mr24
d
5mr22
answer is D.
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Detailed Solution
According to the diagram moment of inertia of the vertical ring about the given axis is I1= mr2+mr2=2mr2 and moment of inertia of the horizontal ring is I2 =mr22 Moment of inertia of the system is I1 +I2= 2mr2+mr22= 5mr22