Two rods A and B of equal free lengths hang vertically from ceiling 60 cm apart and at bottom attached to a light horizontal bar. The bar remain in horizontal position when carry a load of 5000 kg at a distance 20 cm from rod A. If the stress in rod B is 50 N/mm2, find the stress in A (in N/mm2) up to two decimal places. Take Young's moduli are YB=9×1010 N/m2,YA=2×1011 N/m2 and g=10 m/s2.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
333.33 N/mm2
b
222.22 N/mm2
c
111.11 N/mm2
d
55.55 N/mm2
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
For equilibrium of system, we use T1+T2=5000g=5×104 __________ (i)T1(20)=T2(40)⇒T1=2T2 _________ (ii)from (i) and (ii) T2=5×1043N & T1=1053NAs bar remain horizontal⇒ (strain)A =( Strain )B (stress)aya=(stress)bybfor A ⇒(stress)A=yAyB( stress )B=2×10119×1010×50 N/mm2=10009N/mm2=111.11 N/mm2