Q.

Two rods  A and B of same length and radius are joined together end to end. The thermal  conductivity of A and B are 2K  and K. Under steady state conditions, if temperature difference between  the open ends of A and B is 360C, the temperature difference across 'A' is

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a

120C

b

180C

c

240C

d

90C

answer is A.

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Detailed Solution

where Δθ = Temp. difference; Rt = Thermal resistance = l\kAFor the rod A, For the rod B, ⇒ ΔθB = 2.ΔθANow ΔθA + ΔθB = 360CΔθA + 2.ΔθA = 360C ⇒ ΔθA = 120C
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