Two rods A and B of same length and radius are joined together end to end. The thermal conductivity of A and B are 2K and K. Under steady state conditions, if temperature difference between the open ends of A and B is 360C, the temperature difference across 'A' is
where Δθ = Temp. difference; Rt = Thermal resistance = l\kA
For the rod A,
For the rod B,
⇒ ΔθB = 2.ΔθA
Now ΔθA + ΔθB = 360C
ΔθA + 2.ΔθA = 360C ⇒ ΔθA = 120C