Two rods of length d1 and d2 and coefficients of thermal conductivities K1 and K2 are kept touching each other. Both have the same area of cross-section. The equivalent of thermal conductivity is

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K1+K2

K1 d1+K2 d2

d1 K1+d2 K2 d1+d2

d1+d2d1/K1+d2/K2

answer is D.

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Detailed Solution

When two rods are connected in series Q=A(T1−T2)td1 K1+d2 K1=A(T1−T2)t(d1+d2)/K⇒d1+d2 K=d1 K1+d2 K2⇒K=(d1+d2)d1 K1+d2 K2

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