Two rods one of aluminum length I1, having coefficient of linear expansion α1 and other of steel of length l2 having coefficient of linear expansion α2 are joined end to the end. The expansion in both the rods is same for the same variation in temperature. Then the value l1/l1+l2 is
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a
α2/α1
b
α1/α2
c
α1+α2/α2
d
α1/α2+α2
answer is D.
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Detailed Solution
Here α1l1t=α2l2tor α1l1=α2b2 ∴ l2l1=α1α2or l2+l1l1=α1+α2α2 or l1l1+l2=α2α1+α2