First slide

Ohm's law

Question

Two rods of same material and length have their electric resistance in ratio I : 2. When both rods are dipped in water, the correct statement will be

Moderate

A

A has more loss of weight
B

B has more loss of weight
C

both have same loss of weight
D

loss of weight will be in the ratio 1 : 2

Solution

$R = ρ \frac{l}{A} \Rightarrow \frac{R_{1}}{R_{2}} = \frac{A_{2}}{A_{1}} (ρ, L c o n s \tan t) \Rightarrow \frac{A_{2}}{A_{1}} = \frac{R_{2}}{R_{1}} = 2$
Now, when a body dipped in water, loss of weight
$= V σ_{L} g = A L σ_{L} g$
So, $\frac{{(L o s s o f w e i g h t)}_{1}}{{(L o s s o f w e i g h t)}_{2}} = \frac{A_{1}}{A_{2}} = 2;$ so A has more loss of weight.

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