Two rotating bodies  A and  B of masses m,2m with moments of inertia lA andIB,IB>IB have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then

Here, mA=m,mB=2m Both bodies A and B have equal kinetic energy of rotation kA=kB⇒12IAωA2=12IBωB2⇒ωA2ωB2=IBIA…………(1)Ratio of angular momenta, LALB=IAωAIBωB=IAIB×IBIA   [Using eqn. =IAIB<1  ∵IB>IA∴LB>LA