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Q.

Two satellite A and B, ratio of masses 3 : 1 are in circular orbits of radii r and 4r. Then ratio of total mechanical energy of A to B is

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a

1 : 3

b

3 : 1

c

3 : 4

d

12 : 1

answer is D.

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Detailed Solution

Total mechanical energy of satellite E=−GMm2r⇒EAEB=mAmB×rBrA⇒31×4rr=121
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Two satellite A and B, ratio of masses 3 : 1 are in circular orbits of radii r and 4r. Then ratio of total mechanical energy of A to B is