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Two S.H.Ms. $s_{1} = a \sin ωt and s_{2} = b \sin ωt$ are superimposed on a particle. The $s_{1} and s_{2}$ are along the directions which make angle 37° with each other.

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the particle will perform S.H.M.

the particle will not perform S.H.M.

the particle will perform periodic motion but not S.H.M.

the motion will not be oscillatory.

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detailed solution

Correct option is A

Resultant displacement will be the vector sum of two displacements:S = S12+S22+2S1S2cos 37° = a2sin2ωt+b2sin2ωt+2ab sin2ωt×45S = a2+b2+8ab5sin ωtWhich shows that the particle will perform SHM.

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Two S.H.Ms. s1 = a sin ωt and s2 = b sin ωt are superimposed on a particle. The s1 and s2 are along the directions which make angle 37° with each other.

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free study material

Two S.H.Ms. $s_{1} = a \sin ωt and s_{2} = b \sin ωt$ are superimposed on a particle. The $s_{1} and s_{2}$ are along the directions which make angle 37° with each other.