Two SHMs with same frequency act on a particle at right angles, i.e., along x and/-axes. If their amplitudes are equal and the phase difference between them is (π/2), then the resultant is:
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a
a straight line inclined at 45" to the x-axis
b
an ellipse with major axis along x-axis
c
an ellipse with major axis along y-axis
d
a circle
answer is D.
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Detailed Solution
Let equations of two SHMs. x=A sinωt+ϕ and y=A sin ωt+ϕ+π2= A cos ωt+ϕTherefore, x2+y2=A2 ⇒Circle
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Two SHMs with same frequency act on a particle at right angles, i.e., along x and/-axes. If their amplitudes are equal and the phase difference between them is (π/2), then the resultant is: