Two SHMs with same frequency act on a particle at right angles, i.e., along x and/-axes. If their amplitudes are equal and the phase difference between them is (π/2), then the resultant is:

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a straight line inclined at 45" to the x-axis

an ellipse with major axis along x-axis

an ellipse with major axis along y-axis

a circle

answer is D.

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Detailed Solution

Let equations of two SHMs. x=A sinωt+ϕ and y=A sin ωt+ϕ+π2= A cos ωt+ϕTherefore, x2+y2=A2 ⇒Circle

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