Two short bar magnets of magnetic moments M each are arranged at the opposite corners of a square of side d such that their centres coincide with the corners and their axes are parallel. If the like poles are in the same direction, the magnetic induction at any of the other corners of the square is
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a
μ04πMd3
b
μ04π2Md3
c
μ04πM2d3
d
μ04πM22d3
answer is A.
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Detailed Solution
Image 40ABCD is a square of side d. Two bar magnets are arranged at the opposite corners B and D of the square. Consider the corner A of the square. The magnetic induction at a due to magnet M1Ba=μ04π⋅2Md3( along BA)Similarly, the magnetic induction at A due to magnet M2Be=μ04π⋅Md3 along ABResultant B=Ba−Be=μ04π×Md3.