Q.

Two short dipoles pk^ and p2k^ are located at (0,0,0) and (1 m, 0, 2 m), respectively. The resultant electric field due to the two dipoles at the point (1 m, 0, 0) is

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a

9p32πε0k^

b

-7p32πε0k^

c

7p32πε0k^

d

none of these

answer is B.

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Detailed Solution

The given point is at the axis of p→2 dipole and at equatorial line of p→ dipole . So , the total field at given point isE→=kp→(1)3+2k(p→/2)(2)3=kp→-1+18=-7pk^32πε0.
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