First slide
Electric dipole
Question

Two short dipoles pk^ and p2k^ are located at (0,0,0) and (1 m, 0, 2 m), respectively. The resultant electric field due to the two dipoles at the point (1 m, 0, 0) is

Difficult
Solution

The given point is at the axis of p2 dipole and at equatorial line of p dipole . So , the total field at given point isE=kp(1)3+2k(p/2)(2)3=kp-1+18=-7pk^32πε0.

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