First slide

Magnetism

Question

Two short magnets each moment $10 {Am}^{2}$ are placed in end- on position so that their centres are 0.1m apart. The force between them is

Easy

A

0.4 N
B

0.5 N
C

0.6 N
D

0.8 N

Solution

When magnets are along the line joining their centres is
$F = \frac{μ_{0}}{4 π} \frac{6 M_{1} M_{2}}{r^{4}} \Rightarrow F = \frac{4 π \times 10^{- 7}}{4 π} \frac{6 \times 10^{2}}{10^{- 4}} = 0.6 N$

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