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Q.

Two similar springs P and Q have spring constants Kp and KQ, such that KP>KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ  are related as, in case (a) and case (b) respectively

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a

Wp>WQ;WQ>WP

b

WP

c

WP=WQ;WP>WQ

d

WP=WQ;WP=WQ

answer is A.

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Detailed Solution

Here, Kp>KQ Case (a): Elongation (x) in each spring is same. WP=12Kpx2,WQ=12KQx2∴ WP>WQ Case (b): Force of elongation is same.  So, x1=FKP and x2=FKQWP=12KPx12=12F2KPWQ=12KQx22=12F2KQ ∴ WP
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