Two simple harmonic motions are represented by the equations $$y1=0$$â$$1sin$$â¡$$100$$Ï$$t+$$Ï$$3$$ and $$y2=0$$â$$1cos$$â¡(100$$Ï$$t) The phase difference of the velocity of particle $$1$$ with respect to the velocity of particle $$2$$ is

Question

Two simple harmonic motions are represented by the equations $$y1=0$$â$$1sin$$â¡$$100$$Ï$$t+$$Ï$$3$$ and $$y2=0$$â$$1cos$$â¡(100$$Ï$$t) The phase difference of the velocity of particle $$1$$ with respect to the velocity of particle $$2$$ is

Infinity Learn · Accepted Answer

From the given eqs. $$dy1dt=v1=0$$â$$1$$Ã$$100$$Ï$$cos$$â¡$$100$$Ï$$t+$$Ï$$3Similarly$$ $$v2$$ $$=$$ $$dy2dt$$ $$=$$ $$-0.1$$Ã$$100$$Ï $$sin$$ $$100$$Ït $$=$$ $$0.1$$Ã$$100$$Ï $$cos$$ $$(100$$Ït $$+$$Ï$$2)Therefore$$ â³Ï $$=$$ Ï$$3-$$Ï$$2$$ $$=$$ $$-$$Ï$$6$$

Two simple harmonic motions are represented by the equations $y_{1} = 0 â 1 \sin â¡ [100 Ït + \frac{Ï}{3}]$ and $y_{2} = 0 â 1 \cos â¡ (100 Ït)$ The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

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Two simple harmonic motions are represented by the equations y1=0â 1sinâ¡100Ït+Ï3 and y2=0â 1cosâ¡(100Ït) The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Two simple harmonic motions are represented by the equations $y_{1} = 0 â 1 \sin â¡ [100 Ït + \frac{Ï}{3}]$ and $y_{2} = 0 â 1 \cos â¡ (100 Ït)$ The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is