First slide

Simple hormonic motion

Question

Two simple harmonic motions are represented by the equations $y_{1} = 0 â 1 \sin â¡ [100 Ït + \frac{Ï}{3}]$ and $y_{2} = 0 â 1 \cos â¡ (100 Ït)$ The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

Moderate

A

$Ï / 6$
B

$Ï / 3$
C

$â Ï / 6$
D

$â Ï / 3$

Solution

From the given eqs. $\frac{{dy}_{1}}{dt} = v_{1} = 0 â 1 Ã 100 Ïcos â¡ [100 Ït + \frac{Ï}{3}]$
Similarly $v_{2} = \frac{d y_{2}}{d t} = - 0.1 Ã 100 Ï \sin 100 Ït = 0.1 Ã 100 Ï \cos (100 Ït + \frac{Ï}{2})$
Therefore $â³ Ï = \frac{Ï}{3} - \frac{Ï}{2} = - \frac{Ï}{6}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App