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Q.

Two simple harmonic motions are represented by the equations y1=0.1sin100πt+π3 and  y2=0.1cosπt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

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a

−π3

b

π6

c

−π6

d

π3

answer is C.

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Detailed Solution

v1=dy1dt=0.1×100πcos100πt+π3v2=dy2dt=−0.1πsinπt=0.1πcosπt+π2Phase difference of velocity of first particle with respect to the velocity of 2nd particle at t = 0 is Δφ=φ1−φ2=π3−π2=−π6.
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