Two simple harmonic motions are represented by the equations $$y1=0.1sin100$$$$π$$$$t+$$π$$3$$ and $$y2=0.1cos$$$$π$$t. The phase difference of the velocity of particle $$1$$ with respect to the velocity of particle $$2$$ is

Question

Two simple harmonic motions are represented by the equations $$y1=0.1sin100$$$$π$$$$t+$$π$$3$$ and  $$y2=0.1cos$$$$π$$t. The phase difference of the velocity of particle $$1$$ with respect to the velocity of particle $$2$$ is

Infinity Learn · Accepted Answer

$$v1=dy1dt=0.1$$×$$100$$$$π$$$$cos100$$$$π$$$$t+$$π$$3v2=dy2dt=$$−$$0.1$$$$π$$$$sin$$$$π$$$$t=0.1$$$$π$$$$cos$$$$π$$$$t+$$π$$2Phase$$ difference of velocity of first particle with respect to the velocity of $$2nd$$ particle at t $$=$$ $$0$$ is Δφ$$=$$φ$$1$$−φ$$2=$$π$$3$$−π$$2=$$−π$$6$$.

Two simple harmonic motions are represented by the equations $y_{1} = 0 .1 \sin (100 πt + \frac{π}{3})$ and $y_{2} = 0 .1 cosπt .$ The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

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Two simple harmonic motions are represented by the equations y1=0.1sin100πt+π3 and y2=0.1cosπt. The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is

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Two simple harmonic motions are represented by the equations $y_{1} = 0 .1 \sin (100 πt + \frac{π}{3})$ and $y_{2} = 0 .1 cosπt .$ The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is