Two simple harmonic motions are represented by the equations $$y1=0.1$$ $$sin$$ $$100$$$$π$$$$t+$$π$$3$$ and $$y2=0.1$$ $$cos$$ πt.The phase difference of the velocity of particle l, with respect to the velocity of particle $$2$$ is :

Question

Two simple harmonic motions are represented by the equations $$y1=0.1$$ $$sin$$ $$100$$$$π$$$$t+$$π$$3$$ and $$y2=0.1$$ $$cos$$ πt.The phase difference of the velocity of particle l, with respect  to the velocity of particle $$2$$ is :

Infinity Learn · Accepted Answer

$$v1=dy1dt=0.1$$×$$100$$ π $$cos$$ $$100$$$$π$$$$t+$$π$$3$$                  $$=10$$ π $$cos$$ $$100$$ π$$t+$$π$$3$$      $$v2=dy2dt=0.1$$×$$100$$π $$sin$$ $$(100$$ π$$t)=10$$ π$$cos$$$$π$$$$2+100$$$$π$$t ∴    Phase difference $$=$$π$$3-$$π$$2=-$$π$$6$$

Two simple harmonic motions are represented by the equations $y_{1} = 0.1 \sin (100 πt + \frac{π}{3}) and y_{2} = 0.1 \cos πt .$ The phase difference of the velocity of particle l, with respect to the velocity of particle 2 is :

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Two simple harmonic motions are represented by the equations y1=0.1 sin 100πt+π3 and y2=0.1 cos πt.The phase difference of the velocity of particle l, with respect to the velocity of particle 2 is :

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Two simple harmonic motions are represented by the equations $y_{1} = 0.1 \sin (100 πt + \frac{π}{3}) and y_{2} = 0.1 \cos πt .$ The phase difference of the velocity of particle l, with respect to the velocity of particle 2 is :