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Q.

Two simple harmonic motions are represented by y1=5sin 2πt+3 cos 2πt  y2=5 sin 2πt+π4The ratio of the amplitude of two SHM's is:

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a

1 :1

b

1 : 2

c

2 :1

d

1:3

answer is C.

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Detailed Solution

y1=5×212sin 2πt +32cos 2πt     =10sin 2πt cosπ3+cos 2πt sinπ3        y1=10 sin 2πt+π3       y2=5 sin 2πt+π4 ⇒   A1A2=105=21
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