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Questions  

Two simple harmonic motions are represented by 
y1=5sin 2πt+3 cos 2πt  y2=5 sin 2πt+π4
The ratio of the amplitude of two SHM's is:

a
1 :1
b
1 : 2
c
2 :1
d
1:3

detailed solution

Correct option is C

y1=5×212sin 2πt +32cos 2πt     =10sin 2πt cosπ3+cos 2πt sinπ3        y1=10 sin 2πt+π3       y2=5 sin 2πt+π4 ⇒   A1A2=105=21

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