Download the app

Questions  

Two simple harmonic motions given by x1=Acosωt and x2=Asinωt are superposed on a single particle. Then the particle starts its motion from a point whose distance from equilibrium position is

a
A
b
A/2
c
A/2
d
A/22

detailed solution

Correct option is A

Resultant distance from equilibrium position is x=x1+x2=Asinωt+Acosωt⇒x=2A.cosωt−π4The particle starts its motion at t = 0.∴ Initially x=2Acosω×0−π4=A

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A charged particle is deflected by two mutually perpendicular oscillating electric fields such that the displacement of the particle due to each one of them is given by x = A sin (ωt) and y = A sin (ωt+π6) respectively. The trajectory followed by the charged particle is


phone icon
whats app icon