Two simple harmonic motions given by x1=Acosωt and x2=Asinωt are superposed on a single particle. Then the particle starts its motion from a point whose distance from equilibrium position is
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a
A
b
A/2
c
A/2
d
A/22
answer is A.
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Detailed Solution
Resultant distance from equilibrium position is x=x1+x2=Asinωt+Acosωt⇒x=2A.cosωt−π4The particle starts its motion at t = 0.∴ Initially x=2Acosω×0−π4=A