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Two simple harmonic motions given by x1=3cos10t​ cm and x2=4sin10tcm are superposed on a particle. Then amplitude of motion of the particle is 

a
7 cm
b
52 cm
c
2 cm
d
5 cm

detailed solution

Correct option is D

x1=3cos⁡10t and x2=4cos⁡(10t−π2)∴ AR=32+42 cm=5 cm

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