Two simple harmonic motions x1=2 cos100πt and x2=2 sin100πt are superimposed on a particle. If x1 and x2 are in cm and t is in second, the maximum velocity of the particle is (in m/s)
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a
42π
b
2π
c
22π
d
2π
answer is C.
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Detailed Solution
x=x1+x2=(2 cos100 πt+2 sin100 πt) cm⇒x=22 cos 100πt-π4 cm∴Vmax=Aω=22 x 100π cm/s = 22π m/s