Questions
Two simple harmonic oscillators with amplitudes in the ratio 1:2 are having the same total energy, the ratio of their frequencies is
a
1:4
b
1:2
c
2:1
d
4:1
detailed solution
Correct option is C
if amplitude A1=A then A2=2A total energy of both oscillators is same total energy=12mw2A2 12mw12A12=12mw22A22 ⇒ 12mw12A2=12mw2222A2 ⇒ w21w22=4 take square root ⇒ w1w2=2 ⇒2πf12πf2=2 ⇒f1f2=2 \Talk to our academic expert!
Similar Questions
When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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