Questions
Two slabs A and B of different materials but of the same thickness are joined end- to-end to form a composite slab. The thermal conductivities of A and B are K1 and K2, respectively. A steady temperature difference of 120C is maintained across the composite slab. If the temperature difference across slab A is
detailed solution
Correct option is C
The given situation can be shown as below. Rate of flow of heat will be equal in both the slabs,(12−x)K1=K2(x−0)12−x=2x⇒ x=40C ∵K1=K22The temperature difference across slab,A=(12−x)=(12−4)=8∘CTalk to our academic expert!
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A body of length 1 m having cross sectional area has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if K = 200 J
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