Two slabs A and B of equal surface area are placed one over the other such that their surfaces are completely in contact. The thickness and coefficient of thermal conductivities of slab A is twice that of B. The first surface of slab A is maintained at 100°C , while the second surface of slab B is maintained at 25°C . The temperature at the contact of their surfaces is

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15°C

62.5°C

55°C

85°C

answer is B.

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Detailed Solution

QtA=QtB⇒2K(100−θ)2l=K(θ−25)l

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