Two slits are separated by 0.3 mm. A beam of 500 nm light strikes the slits producing an interference pattern. The number of maximas observed in the angular range −30°<θ<30° are 590+p . Calculate p = ?

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answer is 0009.00.

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Detailed Solution

dsinθ=n λ⇒ n=dsinθλ=0.3×10-3x0.5500×10-9=300 excluding central maximum 300-1 =299 on each side Total maximas299 + 299 + 1 = 599 =590+p⇒p=9

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