First slide

In YDSE one of the slits is covered with a thin transparent sheet

Question

Two slits separated by a distance of 1 mm are illuminated with red light of wavelength 6.5 x 10^-7 m.The interference fringes are observed on a screen placed 1m from the slits. The distance between third dark fringe and the fifth bright fringe is equal to

Easy

A

0.65 mm
B

1.63 mm
C

3.25 mm
D

4.88mm

Solution

$β= \frac{5 λ D}{2 d} = \frac{5 \times 6 \cdot 5 \times 10^{- 7} \times (1)}{(10^{- 3})} = 5 \times 0 .65 \times 10^{- 3} m = 3.25 mm The distance between lifth bright fringe from third dark hinge$

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