Two slits separated by a distance of 1 mm are illuminated with light of wavelength 6 .0 x 10 -7 m. The interference fringes are observed on a screen placed 1 m from the slits. The distance between third dark fringe and the fifth bright fringe is equal to
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a
0.60 mm
b
1.50 mm
c
3.00 mm
d
4.50mm
answer is B.
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Detailed Solution
The fringe width p is given byβ=λDd (d= distance between the slits )x=5λD2d=5×6⋅0×10−7×1)2×1×10−3=1.5×10−3mThe fifth bright hinge is separated from third dark hinge by