Two slits separated by a distance of 1 mm, are illuminated with red light of wavelength 6.5 × 10-7 m. The interference fringes are observed on a screen place 1 m from the slits. The distance between the third dark fringe and the fifth bright fringe is equal to
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a
0.65 mm
b
1.63 mm
c
3.25 mm
d
4.88 mm
answer is B.
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Detailed Solution
distance between 3 rd dark and 5 th dark is 2 fringe width and 5th dark to 5 th bright half fringe width so total distance i s 2.5 fringe width 2.5 λDd here D= 1m and d= 10-3m