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Two slits in Youngs experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern,
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Correct option is C
As, intensity I∝ width of slit W Also, intensity I∝ square of amplitude A∴ I1I2=W1W2=A12A22 But W1W2=125 (given) ∴A12A22=125 or A1A2=125=15∴ImaxImin=A1+A22A1-A22=A1A2+12A1A2-12=15+1215-12=652-452=3616=94
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In Young's double slit experiment, the slits are of equal width and maximum intensity of light on the screen is found to be Im. Now one of the slits is covered with a thin sheet of thickness made of material of refractive index 1.2. Then intensity of light at the mid point of the source is
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