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Q.

Two slits in Youngs experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, ImaxImin is

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a

49121

b

49

c

94

d

12149

answer is C.

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Detailed Solution

As, intensity I∝ width of slit W Also, intensity I∝ square of amplitude A∴ I1I2=W1W2=A12A22 But W1W2=125 (given) ∴A12A22=125 or A1A2=125=15∴ImaxImin=A1+A22A1-A22=A1A2+12A1A2-12=15+1215-12=652-452=3616=94

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