Download the app

Questions  

Two slits in Youngs experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, ImaxImin is 

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
49121
b
49
c
94
d
12149
NEW

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

As, intensity I∝ width of slit W  Also, intensity I∝ square of amplitude A∴  I1I2=W1W2=A12A22 But W1W2=125   (given) ∴A12A22=125   or   A1A2=125=15∴ImaxImin=A1+A22A1-A22=A1A2+12A1A2-12=15+1215-12=652-452=3616=94


ctaimg

Similar Questions

In Young's double slit experiment, the slits are of equal width and maximum intensity of light on the screen is found to be Im. Now one of the slits is covered with a thin sheet of thickness 15λ4, made of material of refractive index 1.2. Then intensity of light at the mid point of the source is

Get your all doubts cleared from
Sri Chaitanya experts

counselling
india
+91

phone iconwhats app icon