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Q.

Two small conducting sphere of equal radii have charges + 10 μC and - 20 μC respectively and placed at a distance R from each other experience force F1. If they are brought in contact and separated to the same distance, they experience force F2. The ratio of F1 to F2 is

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a

1:2

b

-8: 1

c

1: 8

d

-2: 1

answer is B.

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Detailed Solution

Here, F1=k(+10)(−20)R2=−k×200R2As spheres are of equal radii, so on touching, the net charge = (+10−20)μC=−10μC, is shared equally between them, i.e. each sphere carries −5μC charge. F2=k(−5)(−5)R2=k×25R2∵F1F2=−81⇒F1:F2=−8:1

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