Two small conducting spheres of equal radius have charges +10 μC and -20 μC respectively and placed at a distance R from each other experience force F1. If they are brought in contact and separated to the same distance, they experience force F2. The ratio of F1 to F2 is

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1 : 8

– 8 : 1

1 : 2

– 2 : 1

answer is B.

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Detailed Solution

F∝Q1Q2⇒F1F2=Q1Q2Q1′Q2′=10×−20−5×−5=−81

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