Two small drops of mercury, each of radius R, coalesce to form a single large drop. The ratio of the total surface energies before and after the change is
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a
1:21/3
b
21/3:1
c
2 : 1
d
1 : 2
answer is B.
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Detailed Solution
The ratio of the total surface energies before and after the change =n1/3:1=21/3:1