First slide

Surface tension and surface energy

Question

Two small drops of mercury, each of radius R, coalesce to form a single large drop. The ratio of the total surface energies before and after the change is

Moderate

A

$1 : 2^{1 / 3}$
B

$2^{1 / 3} : 1$
C

2 : 1
D

1 : 2

Solution

The ratio of the total surface energies before and after the change $= n^{1 / 3} : 1 = 2^{1 / 3} : 1$

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