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Q.

Two solid pieces, one of gold and the other of silver when immersed completely in water have equal weighs. When weighed in air

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a

the gold piece will weigh more

b

the silver piece will weigh more

c

both will have the same weight

d

both will weigh less than they weigh in water

answer is B.

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Detailed Solution

Suppose,Weight of gold in air = xg,Weight of silver in air = ygDensity of gold = d1Density of gold = d2         (where d1 >d2)Volume of gold = xd1, volume of silver = yd2Weight of gold in water =Weigh of silver in wateror (x-xd1×1)g = (y-yd2×1)gor x(1-1d1) = y(1-1d2)or xy = (1-1d2)(1-1d1)< 1 as d1>d2  x < y or y > xi.e., weight of silver in air is more than that of gold in air.
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