Two solid pieces, one of gold and the other of silver when immersed completely in water have equal weighs. When weighed in air
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a
the gold piece will weigh more
b
the silver piece will weigh more
c
both will have the same weight
d
both will weigh less than they weigh in water
answer is B.
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Detailed Solution
Suppose,Weight of gold in air = xg,Weight of silver in air = ygDensity of gold = d1Density of gold = d2 (where d1 >d2)Volume of gold = xd1, volume of silver = yd2Weight of gold in water =Weigh of silver in wateror (x-xd1×1)g = (y-yd2×1)gor x(1-1d1) = y(1-1d2)or xy = (1-1d2)(1-1d1)< 1 as d1>d2 x < y or y > xi.e., weight of silver in air is more than that of gold in air.