Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a light string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with some tension in the string. The arrangement is not possible if
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a
dA
b
dB>dF
c
dA>dF
d
dA+dB=2dF
answer is C.
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Detailed Solution
Equilibrium: B1+B2=W1+W2 dF(V+V)g=Vg(dA+dB) 2dF=(dA+dB)→(1) If dBdF