Two sound sources emitting sound each of wavelength λ, are fixed at a given distance apart. A listener moves with a velocity vo along the line joining the two sources. The number of beats heard by him per second is
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a
vo/2λ
b
2vo/λ
c
vo/λ
d
vo/3λ
answer is B.
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Detailed Solution
Apparent frequency received from the front source n′=v+v0V×Vλ ∵vs=0= source stationary Apparent frequency received from the rear source=V−V0V×Vλ=V−V0λ Number of beats =n′−n′′=V+V0λ−V−v0λ=2v0λ