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Q.

Two sound sources emitting sound each of wavelength λ, are fixed at a given distance apart. A listener moves with a velocity vo along the line joining the two sources. The number of beats heard by him per second is

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a

vo/2λ

b

2vo/λ

c

vo/λ

d

vo/3λ

answer is B.

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Detailed Solution

Apparent frequency received from the front source n′=v+v0V×Vλ ∵vs=0= source stationary  Apparent frequency received from the rear source=V−V0V×Vλ=V−V0λ Number of beats =n′−n′′=V+V0λ−V−v0λ=2v0λ
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