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Q.

Two sound waves of relative intensities 400 : 1 show interference. The ratio of intensity at the maxima to minima is close to

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a

11/9

b

401 /399

c

21 /19

d

401 /399

answer is A.

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Detailed Solution

I∝a2At maxima a′=a1+a2At maxima a′′=a1−a2Given that relative intensities are 400 : 1 r'.e., amplitudes arc in the ratio 20 : 1Ratio of intensity at maxima =(20+1)2(20−1)2=(21)2(19)2≈119
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