Two sound waves of relative intensities 400 : 1 show interference. The ratio of intensity at the maxima to minima is close to
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a
11/9
b
401 /399
c
21 /19
d
401 /399
answer is A.
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Detailed Solution
I∝a2At maxima a′=a1+a2At maxima a′′=a1−a2Given that relative intensities are 400 : 1 r'.e., amplitudes arc in the ratio 20 : 1Ratio of intensity at maxima =(20+1)2(20−1)2=(21)2(19)2≈119