First slide

Charaterstics of sound

Question

Two sound waves of relative intensities 400 : 1 show interference. The ratio of intensity at the maxima to minima is close to

Moderate

A

11/9
B

401 /399
C

21 /19
D

$\sqrt{401 / 399}$

Solution

$I \propto a^{2}$
At maxima $a^{'} = a_{1} + a_{2}$
At maxima $a^{''} = a_{1} - a_{2}$
Given that relative intensities are 400 : 1 r'.e., amplitudes arc in the ratio 20 : 1
Ratio of intensity at maxima = $\frac{(20 + 1)^{2}}{(20 - 1)^{2}}$
$= \frac{(21)^{2}}{(19)^{2}} \approx \frac{11}{9}$

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