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Q.

Two sources A and B are sending notes of frequency 680 Hz. A listener moves from A to B with a constant velocity 'u'. If the speed of sound in air is 340 ms–1, what must be the value 'u' so that he hears 10 beats per second ?

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a

2.0 m-s–1

b

2.5 m-s–1

c

3.0 m-s–1

d

3.5 m-s–1

answer is B.

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Detailed Solution

The listner receives two frequencies, apparent frequency f1 fro source A and apparent frequency f2 for source B.For source B apparent frequency f2,  fb-f2-f1=2f0voV=2×680×v0340=10 v0=2.5 m/s
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