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Q.

Two sources A and B are sounding notes of frequency 680 Hz. A listener moves from A to B with a constant velocity u. If speed of sound is 340 ms-1, what should be the value of u so that he hears 10 beats/s ?

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a

2.0 ms-1

b

3.0 ms-1

c

2.5 ms-1

d

3.5 ms-1

answer is C.

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Detailed Solution

S1A→US2BHe is approaching S2n2=u+uounAnd going away from S1n1=u−uounn2−n1=10u+uoun−u−uoun=2uonu=10uo=10×3402×680=2.5 m/s
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